Make Sass Linear Gradient Mixins Behave in IE
Don’t end up black and blue
I wrote this fairly straightforward cross-browser linear gradient mixin:
@mixin gradient($from-color, $to-color) {
background-color: mix($from-color, $to-color); /* Fallback */
background-image: -webkit-gradient(linear, 0% 0%, 0% 100%, from($from-color), to($to-color));
background-image: -webkit-linear-gradient(top, $from-color, $to-color);
background-image: -moz-linear-gradient(top, $from-color, $to-color);
background-image: -ms-linear-gradient(top, $from-color, $to-color);
background-image: -o-linear-gradient(top, $from-color, $to-color);
-ms-filter: "progid:DXImageTransform.Microsoft.gradient(startColorStr='$from-color', EndColorStr='$to-color')";
}At first blush, this should work, right? However, and in retrospect I shouldn’t have been surprised by this at all, it was doing some seriously weird stuff in IE. I checked the compiled CSS; and Sass skipped parsing the variables in the -ms-filter attribute, passing the variable names through like nothing ever happened. (Apparently if -ms-filter doesn’t get starting and ending colour values it understands, it picks blue and black. And now you know.)
I poked around some and came across this blog post from Josh Rubinstein, who was having the same problem. It turns out that -ms-filter, being a proprietary extension, doesn’t get recognised by Sass – when it comes along, Sass just throws its virtual hands up and passes the name of the variable.
So what to do about it then? Sass’s interpolation syntax to the rescue! What you need to do is wrap your variables like so: #{$from-color}. That way, Sass will parse your colour values, and all our browsers will live happily ever after. Here’s the fully-functional mixin:
@mixin gradient($from-color, $to-color) {
background-color: mix($from-color, $to-color); /* Fallback */
background-image: -webkit-gradient(linear, 0% 0%, 0% 100%, from($from-color), to($to-color));
background-image: -webkit-linear-gradient(top, $from-color, $to-color);
background-image: -moz-linear-gradient(top, $from-color, $to-color);
background-image: -ms-linear-gradient(top, $from-color, $to-color);
background-image: -o-linear-gradient(top, $from-color, $to-color);
-ms-filter: "progid:DXImageTransform.Microsoft.gradient(startColorStr='#{$from-color}', EndColorStr='#{$to-color}')";
}